践行者初中物理电学典题详解第805题解析
解析步骤与数据
| 步骤 | 公式/计算过程 | 结果 |
|---|---|---|
| 1 | RL = (UL额)²/PL额 = (12V)²/6W | RL = 24Ω |
| 2 | 无 | 无 |
| 3 | R中 = aΩ/2，U0中 = 3V，I = U0中/R中 = 6A/a，U = U0中 + IRL = 3V + 6A/a × 24Ω | U = 3V + 144V/a |
| 4 | Rmax = aΩ，U0b = 5V，I = U0b/Rmax = 5A/a，U = U0b + IRL = 5V + 5A/a × 24Ω | U = 5V + 120V/a |
| 5 | ΔU0 = U0b – U0中 = 2V，ΔL = ΔU0/RL = 2V/24Ω = 1A/12，ΔL = U0中/R中 – U0b/Rb = 3V/aΩ/2 – 5V/aΩ = 6ΩA/a – 5A/a = 1A/aΩ，1A/aΩ = 1A/12Ω | a = 12Ω，U = U0 + IRL = 5V + 5V × 24Ω/12Ω |
解析
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